Need some help with a calculus problem - Mustang Evolution

Go Back   Mustang Evolution > Off Topic Forums > The Bar



Reply
 
Thread Tools Search this Thread
Please support our sponsors and let them know you heard about them here!
Old 10-28-2004, 11:49 AM   #1
Registered Member
Regular
 
BruThru2002's Avatar
 
Join Date: Sep 2003
Posts: 44
Send a message via AIM to BruThru2002
Need some help with a calculus problem

having some trouble with the last question on my assignment. It is dealing with derivatives. Here it is:

Suppose a ball is tossed upward so that its height in feet after t seconds is
h(t) = -16t^2 + 48t + 4
Recall that position' = velocity and that velocity' = acceleration.

a)When does the ball reach its peak?
b)How high is the ball at its peak?
c)When does the ball hit the ground?
d)How fast is it going when it hits the ground?
e)Verify and explain why the ball's acceleration is always -16 ft/sec/sec

can anyone help?!?!?
__________________

2000 Mustang....
~ Performance Red, New Mach 1 (Mag 500) rims, Dual Flowmaster Exhaust, Black Letters & Rocker stripes, Sony - Rockford Fosgate system
-Billy
BruThru2002 is offline   Reply With Quote
Sponsored Links
Advertisement
 
Old 10-28-2004, 01:40 PM   #2
Registered User
Regular
 
Brent's Avatar
 
Join Date: May 2003
Region: Tennessee
Posts: 11,873
pm Ken
__________________

Reddit
Brent is offline   Reply With Quote
Old 10-28-2004, 01:48 PM   #3
Legacy Member
Legacy
 
MarkuzLS1's Avatar
 
Join Date: Jul 2004
Region: Alabama
Posts: 1,426
Send a message via AIM to MarkuzLS1
Quote:
a)When does the ball reach its peak?
b)How high is the ball at its peak?
c)When does the ball hit the ground?
d)How fast is it going when it hits the ground?
e)Verify and explain why the ball's acceleration is always -16 ft/sec/sec
a)Take the first derivitive (gives you the equation for speed by time) and solve it for zero . That's the amount of time it takes for the ball to quit moving.

b)Plug in your answer for a into your original equation.

c)twice your answer for a.

d)Plug in the time from c into the first derivitive equation you found in a

e)The acceleration of gravity is 16 ft/sec^2. Since your equation gives height, it's -16 ft/sec^2. I'm not sure how your teacher wants you to verify it.
__________________

I like turtles.
MarkuzLS1 is offline   Reply With Quote
Sponsored Links
Advertisement
 
Old 10-28-2004, 02:01 PM   #4
Legacy Member
Legacy
 
Join Date: May 2003
Region: Pennsylvania
Posts: 381
Quote:
Originally Posted by MarkuzLS1
a)Take the first derivitive (gives you the equation for speed by time) and solve it for zero . That's the amount of time it takes for the ball to quit moving.

b)Plug in your answer for a into your original equation.

c)twice your answer for a.

d)Plug in the time from c into the first derivitive equation you found in a

e)The acceleration of gravity is 16 ft/sec^2. Since your equation gives height, it's -16 ft/sec^2. I'm not sure how your teacher wants you to verify it.
I agree but i'm pretty sure acceleration of gravity is -32 ft/sec^2 this can be verified by taking the second derivitive of the position function so i'm confused as to why it says prove that it is always -16 ft/sec^2
__________________

-Denver
2002 Mineral Grey GT, 5-speed: MGW short throw, JLT CAI: SOLD
2002 Electric Green V6, Auto: SOLD
greenpony02 is offline   Reply With Quote
Old 10-28-2004, 02:13 PM   #5
Registered Member
Regular
 
BruThru2002's Avatar
 
Join Date: Sep 2003
Posts: 44
Send a message via AIM to BruThru2002
Thanks for the help guys.... I actually got them right.
__________________

2000 Mustang....
~ Performance Red, New Mach 1 (Mag 500) rims, Dual Flowmaster Exhaust, Black Letters & Rocker stripes, Sony - Rockford Fosgate system
-Billy
BruThru2002 is offline   Reply With Quote
Old 10-28-2004, 02:33 PM   #6
Legacy Member
Legacy
 
Join Date: Oct 2003
Posts: 529
Send a message via AIM to whipster24 Send a message via Yahoo to whipster24
yeah, it definitely should say 32 ft/s^2 there.

always remember to think of what each derivative is and what setting that to zero means. Finding things like maximum height, maximum/minimum velocity, are found by using derivatives and setting them equal to zero to solve for the time.
__________________


"This year will go down in history. For the first time, a civilized nation has full gun registration. Our streets will be safer, our police more efficient, and the world will follow our lead into the future!"
-Adolf Hitler, 1935
whipster24 is offline   Reply With Quote
Reply

Lower Navigation
Go Back   Mustang Evolution > Off Topic Forums > The Bar

Thread Tools Search this Thread
Search this Thread:

Advanced Search

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are Off


Similar Threads
Thread Thread Starter Forum Replies Last Post
97 A/C problem phaw16 1996-2004 Mustang GT 7 07-20-2009 01:39 PM
Our problem gdcpony The Bar 10 06-30-2008 02:01 AM
Problem.. lowflyn Pre-2005 V6 Mustang 15 07-25-2005 01:52 PM

» Like Us On Facebook



03:10 PM


Powered by vBulletin® Version 3.8.8
Copyright ©2000 - 2017, vBulletin Solutions, Inc.
Content Relevant URLs by vBSEO 3.6.0

MustangEvolution.com is in no way associated with or endorsed by Ford Motor Company.